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a1 = {1:"A",2:"B",3:"C"} b1 = {4:"D",5:"E"} b1.update(a1) print(b1)
Correct Answer: {4: 'D', 5: 'E', 1: 'A', 2: 'B', 3: 'C'}
A=[[1,2,3],[4,5,6],[7,8,9]] print(A[1][:])
Correct Answer: [4, 5, 6]
t = (2, 3, 4, 3.5, 5, 6) print(sum(t) + t.count(2))
Correct Answer: 25.5
Correct Answer: del d["john"]
Correct Answer: All of these
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